SOLUTION: ticket prices at concert were $10 for adults, $7 for seniors, and $5 for children. there were twice as many children as adults and 3 more seniors than adults. if the total receipts

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: ticket prices at concert were $10 for adults, $7 for seniors, and $5 for children. there were twice as many children as adults and 3 more seniors than adults. if the total receipts      Log On


   



Question 164049: ticket prices at concert were $10 for adults, $7 for seniors, and $5 for children. there were twice as many children as adults and 3 more seniors than adults. if the total receipts for the concert were $1236, how many children were in attendance?
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Let x = number adult tickets
then
from "there were twice as many children as adults"
2x = number of children tickets
and
from "3 more seniors than adults"
x+3 = number senior tickets
.
Because we know the "total receipts for the concert were $1236" we have:
10x + 7(x+3) + 5(2x) = 1236
10x + 7x+21 + 10x = 1236
27x + 21 = 1236
27x = 1215
x = 45 (adult tickets)
.
children tickets:
2x = 2(45) = 90 (children tickets)
.
senior tickets:
x+3 = 45+3 = 48 (senior tickets)