Question 164019: An office supply store sells three models of computer desk: A, B, and C. In January, the store sold a total of 85 computer desks. The number of model B desks was five more than the number of model C desks, and the number of model A desks was four more than twice the number of model C desks. How many of each model did the store sell in January?
Answer by aka042(26)   (Show Source):
You can put this solution on YOUR website! If A, B, and C are the number of A model, B model, and C model desks respectively, then we know that in Jan, A + B + C = 85. We are told that the number of b desks was five more than the number of C desks, so B = C + 5. Furthermore, the number of A desks was four more than twice the number of C desks, so A = 4 + 2*C. Now we just substitute for A and B in our initial equation:
 . This reduces to  or  which implies c = 76/4 = 19. Therefore 19 c desks were sold. We know can determine that the number of B desks sold was B = C + 5 = 19 + 5 = 24, and the number of A desks sold was A = 4 + 2*C = 4+(2*19) = 4+38 = 42. To check, 24 + 42 + 19 = 85.
In summary, 42 A desks were sold, 24 B desks were sold, and 19 c desks were sold.
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