Question 163748: please help me solve find two consecutive integers such that 4 times the largest exceeds 3 times the smaller by 23 Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! X & X+1 ARE THE 2 INTEGERS.
4(X+1)=3X+23
4X+4=3X+23
4X-3X=23-4
X=19 ANSWER.
PROOF:
4(19+1)=3*19+23
4*20=57+23
80=80