Question 163710: The sum of 3 consecutive integers is twice the smallest integer. What are the 3 integers?
Answer by orca(409)   (Show Source):
You can put this solution on YOUR website! Let the three consecutive numbers be n-1, n, n+1.
As the sum of 3 consecutive integers is twice the smallest integer, we have
n - 1 + n + n + 1 = 2(n - 1)
Solving the equation, we obtain:
3n = 2n - 2
n = -2
So the smallest number is n-1=-2-1=-3
the middle number is n = -2
the largest number is n + 1 = -2 + 1 = -1
Thus the three consecutive numbers are -3, -2, -1.
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