SOLUTION: It costs Ave Electronics Company $1900 to manufacture to 10 VCRs and $2200 to manufacture 16 VCRs. At this rate, what would be the cost of manufacturing 25 VCRS?

Algebra ->  College  -> Linear Algebra -> SOLUTION: It costs Ave Electronics Company $1900 to manufacture to 10 VCRs and $2200 to manufacture 16 VCRs. At this rate, what would be the cost of manufacturing 25 VCRS?      Log On


   



Question 163703This question is from textbook algebra and trigonometry
: It costs Ave Electronics Company $1900 to manufacture to 10 VCRs and $2200 to manufacture 16 VCRs. At this rate, what would be the cost of manufacturing 25 VCRS? This question is from textbook algebra and trigonometry

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
(10,1900) & (16,2200)
slope of this rate is:
(2200-1900)/(16-10)
300/6=50
[Y=mX+b]
2200=50*10+b
2200=500+b
b=2200-500
b=1700
y=50x+1700 (red line)
y=50*25+1700
y=1250+1700
y=$2,950 would be the cost to manufacture 25 VCRs.
+graph%28+300%2C+200%2C+-50%2C+35%2C+-1000%2C+3500%2C+50x+%2B1700%29+ (graph 300x200 pixels, x from -50 to 35, y from -1000 to 3500, 50x +1700).