SOLUTION: Please help me: Find the center and the radius of the circle given by x^2+8x+y^2+6y-24=0 Thank you.

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Question 163647: Please help me:
Find the center and the radius of the circle given by x^2+8x+y^2+6y-24=0
Thank you.
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!

Complete the squares in both x and y.
Take 1/2 of both the x and y coefficient and square it.
Add that number to both sides of the equation.
%28x%5E2%2B8x%29%2B%28y%5E2%2B6y%29-24=0
%28x%5E2%2B8x%2B16%29%2B%28y%5E2%2B6y%2B9%29-24=16%2B9
%28x%2B4%29%5E2%2B%28y%2B3%29%5E2-24=25
%28x%2B4%29%5E2%2B%28y%2B3%29%5E2=49
Compare this equation to a general form of a circle centered at (h,k) with a radius, R.
%28x-h%29%5E2%2B%28y-k%29%5E2=R%5E2
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This is an equation of a circle centered at (-4,-3) with a radius of 7.