SOLUTION: how would you graph {{{x^2+y^2=36}}} thanks!!

Algebra ->  Rational-functions -> SOLUTION: how would you graph {{{x^2+y^2=36}}} thanks!!      Log On


   

Question 163644: how would you graph x%5E2%2By%5E2=36
thanks!!
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
x%5E2%2By%5E2=36
y%5E2=36-x%5E2
y=0%2B-sqrt%2836-x%5E2%29
Then choose x values between (-6,6) and get the y values.
X values have to be in that interval for the square root function to make sense.
(-6,0)
(0,6)
(0,-6)
(6,0)
.
.
.
+graph%28+300%2C+300%2C+-7%2C+7%2C+-7%2C+7%2C+-sqrt%2836-x%5E2%29%2Csqrt%2836-x%5E2%29%29%29
.
.
.
The equation is for a circle centered at (0,0) with a radius of 6.
The positive square root gives the top (positive) portion of the graph, the negative square root, the bottom portion of the graph.