SOLUTION: if a=23, b=x², c=x, d=14, and 2b-3c+d=a, what is the value of x?
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-> SOLUTION: if a=23, b=x², c=x, d=14, and 2b-3c+d=a, what is the value of x?
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Question 163521
:
if a=23, b=x², c=x, d=14, and 2b-3c+d=a, what is the value of x?
Answer by
KnightOwlTutor(293)
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2b-3c+d=a replace the variables b,c,d and a with the equivalent values
2x^2-3x+14=23
Subtract 14 from both sides
2x^2-3x=9
Subtract 9 from both sides
2x^2-3x-9=0 This is a quadratic equation
Solved by
pluggable
solver:
SOLVE quadratic equation with variable
Quadratic equation
(in our case
) has the following solutons:
For these solutions to exist, the
discriminant
should not be a negative number.
First, we need to compute the discriminant
:
.
Discriminant d=81 is greater than zero. That means that there are two solutions:
.
Quadratic expression
can be factored:
Again, the answer is: 3, -1.5. Here's your graph: