Question 163505: Solve the following equations.
1) 2x = 7x + 2
2x - 7x = 7x - 7x + 2
-5x = 2
x = -2/5
2) y/5 = 4
y/5 * 5 = 4 * 5 (Multiply both sides by 5)
y = 20
3) x/2 - 3 = 4
x/2 - 3 + 3 = 4 + 3
x/2 = 7 (Multiply both sides by 2)
x = 14
4. OH NUTS! SELLS CASHEWS FOR $6.75 PER POUND AND BRAZIL NUTS FOR $5.00 PER POUND. HOW MUCH OF EACH TYPE SHOULD BE USED TO MAKE A 50lb MIXTURE THAT SELLS FOR $5.70 PER POUND?
5. Try 5x - 7y = 35
What are the x and y intercepts? Graph your answer use any method of your choice to solve.
You can put this solution on YOUR website! The first three problems are correct.
4. x=# of pounds of cashews
50-x=# of pounds of brazil nuts.
5(50-x)+6.75x=5.70(50)
250-5x+6.75x=285
add the x terms to simplify
250+1.75x=285
Subtract 250 from both sides
1.75x=35
Divide both sides by 75
x=20
Let's check our answer
5(30)+6.75(20)=285
150+135=285
5x - 7y = 35
Subtract 5x from both sides
-7y=35-5x
Divide both sides by -7
y=-5+(5/7)x
You can put this solution on YOUR website! 1. Correct
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2. Correct
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3. Correct
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4. Let's call pounds of cashews C, pounds of brazil nuts B.
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4a.
4b.
From eq. 4a, get an expression for C in terms of B.
4a.
Now substitute that expression into eq. 4b and solve for B.
4b.
From eq. 4a,
4a.
B=28.6 lbs, C=21.4 lbs.
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5.X-intercept : Let y=0 solve for x.
X-intercept:(7,0)
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Y-intercept : Let x=0 solve for y.
Y-intercept:(0,-5)
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Graph those two points.
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Now draw the line connecting those two points and extend the line to the edges of your graph.
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