SOLUTION: Four times the largest of three consecutive odd integers decreased by ten is the same as two times the smaller integer increased by 48. What are the odd integers?
Let x; x+2; an
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-> SOLUTION: Four times the largest of three consecutive odd integers decreased by ten is the same as two times the smaller integer increased by 48. What are the odd integers?
Let x; x+2; an
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Question 163294: Four times the largest of three consecutive odd integers decreased by ten is the same as two times the smaller integer increased by 48. What are the odd integers?
Let x; x+2; and x+4 represent the three consecutive odd numbers
then
4(x+4)-10= 2(x)+48
4x+16-10 = 2x + 48
4x+6 = 2x+48
4x-2x+6=2x-2x+48
2x+6 = 0+ 48
2x+6-6 = 48 -6
2x = 42
2x/2 = 42/2
x=21
So the odd integers are 21,23,25 Found 2 solutions by ankor@dixie-net.com, eperette:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! The three consecutive off integers: x, x+2, x+4
:
Just write what it says ("is" means "="):
"Four times the largest of three consecutive odd integers decreased by ten is the same as two times the smaller integer increased by 48."
4(x+4) - 10 = 2x + 48
4x + 16 - 10 = 2x + 48
4x + 6 = 2x + 48
4x - 2x = 48 - 6
2x = 42
x = 21
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The numbers, 21, 23, 25
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Check solution in the given statement:
4(25) - 10 = 2(21) + 48
100 - 10 = 42 + 48
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