SOLUTION: The larger of two consecutive integers is 10 more than 4 times the smaller.Find the integers. This question is on a worksheet isbn 13:978-0-618-72652-3 isbn 10: 0-618-72652-7

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: The larger of two consecutive integers is 10 more than 4 times the smaller.Find the integers. This question is on a worksheet isbn 13:978-0-618-72652-3 isbn 10: 0-618-72652-7      Log On


   

Question 163201: The larger of two consecutive integers is 10 more than 4 times the smaller.Find the integers. This question is on a worksheet
isbn 13:978-0-618-72652-3
isbn 10: 0-618-72652-7
Answer by Anthea Lawn(22) About Me  (Show Source):
You can put this solution on YOUR website!
Call the smaller of the two integers N
The larger of the two integers is the next number up (the problem said they were consecutive), so it must be N+1
The bigger number minus 10 equals the smaller number times four. Let's express that algebraically :
(N + 1) - 10 = 4N
Now, we just go ahead and solve :
N - 9 = 4N
N = -3
Therefore the two numbers are -3 (which is the smaller) and -2 (the larger)