SOLUTION: I just wanted to see if this was correct. If not, can you explain? (3x)^-1/3 simplified is 1/square root of 3 Thanks alot!!!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: I just wanted to see if this was correct. If not, can you explain? (3x)^-1/3 simplified is 1/square root of 3 Thanks alot!!!       Log On


   



Question 163081: I just wanted to see if this was correct. If not, can you explain?
(3x)^-1/3 simplified is 1/square root of 3
Thanks alot!!!

Answer by joecbaseball(37) About Me  (Show Source):
You can put this solution on YOUR website!
No, your answer is not correct.
Any time you have a negative exponent, this is how you handle it:
If the negative exponent appears in the numerator, move the term to the denominator, and the sign of the exponent becomes positive. It works the opposite if the negative exponent appears in the denominator; that is, you move the term to the numerator and change the signs.
So, your problem of (3x)^-1/3 can be rewritten as 1/(3x)^1/3, which is close to what you did.
But now the 1/3 power refers to the CUBED ROOT of the (3x) term, so your answer should be:
1/cubed root of 3x.
So, as a further note, a square root is written as something to the ½ power.
A cubed root is written to the 1/3 power.
A fourth root is written as the ¼ power.
Etc….
Good luck,
JoeC