SOLUTION: Hi, I'm trying to figure out how to set up this problem: Find the measure of an angle such that the difference between the measure of its supplement and 5 times the measure o

Algebra ->  Angles -> SOLUTION: Hi, I'm trying to figure out how to set up this problem: Find the measure of an angle such that the difference between the measure of its supplement and 5 times the measure o      Log On


   

Question 162951: Hi,
I'm trying to figure out how to set up this problem:
Find the measure of an angle such that the difference between the measure of
its supplement and 5 times the measure of the complement is 10 degrees.
This question is on a worksheet that my professor gave us for homework.
I tried setting it up like this:
(180-x) = 5(90-x) - 10
Thank you,
Joan
Found 2 solutions by jim_thompson5910, Earlsdon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
You're close, but the equation should be:

%28180-x%29+-+5%2890-x%29+=+10


180-x-450%2B5x=10 Distribute.


4x-270=10 Combine like terms on the left side.


4x=10%2B270 Add 270 to both sides.


4x=280 Combine like terms on the right side.


x=%28280%29%2F%284%29 Divide both sides by 4 to isolate x.


x=70 Reduce.


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Answer:

So the answer is x=70 which means that the angle is 70 degrees

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Read the problem statement carefully:
Let the angle be x:
"...the difference between the measure of its supplement (180-x) and 5 times its complement (-5(90-x)) is (=) 10 degrees", so...
(180-x)-5(90-x) = 10 Simplify.
180-x-450+5x = 10 Combine like-terms.
-270+4x = 10 Add 270 to both sides.
4x = 280 Divide both sides by 4.
x = 70 degrees.