SOLUTION: Please help me answer the following: Simplify: 1) i^23 2) i^24 Thank you.

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: Please help me answer the following: Simplify: 1) i^23 2) i^24 Thank you.      Log On


   

Question 162872: Please help me answer the following:
Simplify:
1) i^23
2) i^24
Thank you.
Answer by orca(409) About Me  (Show Source):
You can put this solution on YOUR website!
i%5E23+=+i%5E22%2Ai=%28i%5E2%29%5E11%2Ai=%28-1%29%5E11%2Ai=-1%2Ai=-i
Using the result above, we can find i^24
i%5E24+=+i%5E23%2Ai+=%28-i%29%2Ai=-i%5E2=-%28-1%29=1