SOLUTION: Suppose you have a dark closet containing 7 blue shirts, 5 yellow shirts and 8 white shirts. You pick 2 shirts from the closet. Find each probability.
A. P(blue then yellow) wit
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A. P(blue then yellow) wit
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Question 16285: Suppose you have a dark closet containing 7 blue shirts, 5 yellow shirts and 8 white shirts. You pick 2 shirts from the closet. Find each probability.
A. P(blue then yellow) with replacing
B. P (blue then yellow) without replacing
C. P (yellow then yellow) with replacing
D. P (yellow then yellow) without replacing Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! Suppose you have a dark closet containing 7 blue shirts, 5 yellow shirts and 8 white shirts. You pick 2 shirts from the closet. Find each probability.
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A. P(blue then yellow) with replacing
Because you are replacing the selections are independent.
Although the problem says "then" it really means "and".
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P(b and y)=P(b)*P(y)=(7/20)*(5/20)=35/400
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B. P (blue then yellow) without replacing
Now the selections are dependent:
P(b and y)= p(b)*p(y|b) = (7/20)(5/19)=35/380
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C. P (yellow then yellow) with replacing
P(y and y)= (7/20(7/20)=49/400
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D. P (yellow then yellow) without replacing
P(y and y)=P(y)*P(y|y)=5/20 * 4/19= 1/19
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Cheers,
Stan H.
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