SOLUTION: Can some one help me simplify: a) i^23 b) i^24 Thanks.

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Question 162790: Can some one help me simplify:
a) i^23
b) i^24
Thanks.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Note:
i=sqrt%28-1%29, i%5E2=-1,i%5E3=-i, and i%5E4=1.


a)


b) i%5E24=%28i%5E%284%29%29%5E6=%281%29%5E6=1