Question 162751: three consecutive odd integers are such athat the square of the third is 264 more than the square of the second. Find the three integers. Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! three consecutive odd integers are such athat the square of the third is 264 more than the square of the second. Find the three integers.
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Let x = 1st consecutive odd integer
then
x+2 = 2nd consecutive odd integer
x+4 = 3rd consecutive odd integer
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Then from "square of the third is 264 more than the square of the second" we get
(x+4)^2 = (x+2)^2 + 264
expanding:
x^2 + 8x + 16 = (x^2+4x+4) + 264
x^2 + 8x + 16 = x^2 + 4x + 268
8x + 16 = 4x + 268
4x + 16 = 268
4x = 252
x = 63
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Answer: 63, 65, 67
