SOLUTION: (x-3)^2+(x+2)^2=17 (x-3)(x-3) + (x+2)(x+2)=17 (x^2-6x+9) + (x^2+4x+4) =17 x^2 - 6x +9 +x^2 +4x +4 =17 2x^2 -2x + 13 =17 2x^2-2x-4=0 (2x-4)(x+1)=0 2x-4=0 and x+1=0 x=2 a

Algebra ->  Test -> SOLUTION: (x-3)^2+(x+2)^2=17 (x-3)(x-3) + (x+2)(x+2)=17 (x^2-6x+9) + (x^2+4x+4) =17 x^2 - 6x +9 +x^2 +4x +4 =17 2x^2 -2x + 13 =17 2x^2-2x-4=0 (2x-4)(x+1)=0 2x-4=0 and x+1=0 x=2 a      Log On


   

Question 162693This question is from textbook Elementary and Intermediate
: (x-3)^2+(x+2)^2=17
(x-3)(x-3) + (x+2)(x+2)=17
(x^2-6x+9) + (x^2+4x+4) =17
x^2 - 6x +9 +x^2 +4x +4 =17
2x^2 -2x + 13 =17
2x^2-2x-4=0
(2x-4)(x+1)=0
2x-4=0 and x+1=0
x=2 and x=-1 This question is from textbook Elementary and Intermediate

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