SOLUTION: write thev equation of a line in the form Ax+By=C throgh the point (-5,-3)and perpendicular to the line y= - 2over3x+6

Algebra ->  Graphs -> SOLUTION: write thev equation of a line in the form Ax+By=C throgh the point (-5,-3)and perpendicular to the line y= - 2over3x+6      Log On


   

Question 162486: write thev equation of a line in the form Ax+By=C throgh the point (-5,-3)and perpendicular to the line y= - 2over3x+6
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
write the equation of a line in the form Ax+By=C through the point (-5,-3)and perpendicular to the line y= -(2/3)x+6
:
Determine the slope m2, the relationship of perpendicular lines: m1*m2=-1
Let m1 = -2%2F3
-2%2F3*m2 = -1
m2 = -1*-3%2F2
m2 = 3%2F2
:
Use the point/slope formula
y - (-3) = 3%2F2(x - (-5)
y + 3 = 3%2F2(x +5)
y + 3 = 3%2F2x + 15%2F2
y = 3%2F2x + 15%2F2 - 3
y = 3%2F2x + 15%2F2 - 6%2F2
y = 3%2F2x + 9%2F2
Get rid of the denominators multiply equation by 2
2y = 3x + 9
arrange in the required format
-3x + 2y = 9