Question 162455: A Rectangular field whose length is 10 meters longer than its width is to be enclosed with exactly 100 meters of fencing material. What are the dimensions of the field?
Answer by Earlsdon(6294)   (Show Source):
You can put this solution on YOUR website! Let L = the length of the field and W = the width of the field.
From the problem description, you have:
L = W+10 "...length is 10 meters longer than its width..."
The perimeter of a rectangle is given by:
P = 2(L+W) and this is 100 meters, substituting L = W+10 and P = 100, you get:
100 = 2((W+10)+W) Simplifying this, you get:
100 = 2(2W+10) Divide both sides by 2.
50 = (2W+10) Subtracting 10 from both sides gives you:
40 = 2W Finally, dividing both sides by 2, you'll get:
W = 20 and L = W+10 = 20+10 = 30.
The length of the field is 30 meters and the width of the field is 20 meters.
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