Question 162367: Three times the greatest of three consecutive even intigers exceeds twice the least by the 38. Write an equation and Find the intigers. Answer by gonzo(654) (Show Source):
You can put this solution on YOUR website! let x = any even integer.
3 consecutive integers would be:
x
x+2
x+4
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3 times the largest = 2 times the smallest + 38
3 (x + 4) = 2 * (x) + 38
3*x + 12 = 2*x + 38
subtract 2*x from both sides of equation and subtract 12 from both sides of equation to get
x = 26
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smallest number is 26.
largest number is 30.
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substituting in original equation we get
3*(30) = 2*26 + 38
90 = 52 + 38
90 = 90.
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