SOLUTION: Classify the conic section of each equation. 10. 25x^2 - 9y^2 = 144 I think this may be a circle? But im not for sure and I would love to see the correct steps to finding the

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Classify the conic section of each equation. 10. 25x^2 - 9y^2 = 144 I think this may be a circle? But im not for sure and I would love to see the correct steps to finding the      Log On


   



Question 162322: Classify the conic section of each equation.
10. 25x^2 - 9y^2 = 144
I think this may be a circle? But im not for sure and I would love to see the correct steps to finding the answer, i know to rewrite x as x-0 and y as y-0, and i know that 144 is also 12^2,but im not sure where to begin. Thank you!

Found 2 solutions by Alan3354, Fombitz:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Classify the conic section of each equation.
10. 25x^2 - 9y^2 = 144
I think this may be a circle? But im not for sure and I would love to see the correct steps to finding the answer, i know to rewrite x as x-0 and y as y-0, and i know that 144 is also 12^2,but im not sure where to begin. Thank you!
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If it were a plus sign, it would be an ellipse. A circle is a special case of the ellipse, and the coefficients of the x^2 and y^2 terms would be the same.
The minus sign makes it a hyperbola.

Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Three things to check in conic sections: degree of x and y, coefficient and signs of coefficients.
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Circle : Degree 2 for both x and y, equal coefficients, both positive.
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Parabola : Degree 2 for y and degree 1 for y, coefficients not important.
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Ellipse: Degree 2 for both x and y, unequal coefficients, both positive.
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Hyperbola : Degree 2 for both x and y, coefficients not important, one positive, one negative.
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25x%5E2+-+9y%5E2+=+144
x and y degree 2.
Coefficients:One positive, one negative.
Hyperbola.
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.
.
You could also divide by 144 and look for general forms of conic sections.
25x%5E2%2F144-9y%5E2%2F144=1
The general form for a hyperbola is,
%28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1
In your case,
h=0
k=0
a%5E2=%28144%2F25%29
a=12%2F5
b%5E2=%28144%2F9%29
b=12%2F3