Question 162244: Sorry, I wasn't quite sure what to put this in.
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Given the following equation:
1/x = 1/a + 1/b
Tommy tried to solve this, giving his answer x = a + b.
Prove that this solution can never be correct for x > 0
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I've made an attempt at it, i worked on the first equation until i had
x=(ab)/(a+b) Since that value of x is not equal to a + b as Tommy said, my solution says his can't be right. Please tell me if i'm correct and correct me if i'm not :)
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! Given the following equation:
1/x = 1/a + 1/b
Tommy tried to solve this, giving his answer x = a + b.
Prove that this solution can never be correct for x > 0
______________
I've made an attempt at it, i worked on the first equation until i had
x=(ab)/(a+b) Since that value of x is not equal to a + b as Tommy said, my solution says his can't be right. Please tell me if i'm correct and correct me if i'm not :)
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1/x = 1/a + 1/b
1/x = (a+b)/ab
x = ab/(a+b)
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Tommy's answer, whoever that is, is wrong for all values of x, all the time.
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