SOLUTION: I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right s
Algebra ->
Square-cubic-other-roots
-> SOLUTION: I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right s
Log On
Question 162166: I must decide if the algebraic manipulation is correct or incorrect. if it is incorrect I need to fix it or explaine why it cannot be simplified.I don't know if this is the right spot to post but if you can help that would be great.
square root 12x^3 over square root 3x = square root 4x^2 = 2x
You can put this solution on YOUR website! sqrt12x^3/sqrt3x 12can be divided by 3 so we have sqrt4 sqrt4 is a perfect square of 2 x^3+x(-1)=x^2 the sqrt of x^2 is x. 2x is the correct answer. It cannot be simplified any further.
