SOLUTION: Factoring Completely x^3y+2x^2y^2+xy^3 x ( x^2y + 2xy^2 + y^3) xy (x^2 + 2xy + y^2) xy(x + y)(x +y) or xy(x + y )^2

Algebra ->  Test -> SOLUTION: Factoring Completely x^3y+2x^2y^2+xy^3 x ( x^2y + 2xy^2 + y^3) xy (x^2 + 2xy + y^2) xy(x + y)(x +y) or xy(x + y )^2       Log On


   

Question 162113This question is from textbook Elementary and Intermediate
: Factoring Completely
x^3y+2x^2y^2+xy^3
x ( x^2y + 2xy^2 + y^3)
xy (x^2 + 2xy + y^2)
xy(x + y)(x +y)
or
xy(x + y )^2
This question is from textbook Elementary and Intermediate

Found 2 solutions by Earlsdon, eperette:
Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Factor comletely:
x%5E3y%2B2x%5E2y%5E2%2Bxy%5E3 First, factor the common xy.
xy%28x%5E2%2B2xy%2By%5E2%29 Now factor the trinomial.
xy%28x%2By%29%28x%2By%29 or xy%28x%2By%29%5E2

Answer by eperette(173) About Me  (Show Source):