SOLUTION: I am completely lost on this worksheet and have no book. Please help. Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equat

Algebra ->  Matrices-and-determiminant -> SOLUTION: I am completely lost on this worksheet and have no book. Please help. Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equat      Log On


   

Question 162093: I am completely lost on this worksheet and have no book. Please help.
Find the value of the discriminant for 9x^2+1=6x. Then describe the number and type of roots for the equation.
Thanks
Answer by elima(1433) About Me  (Show Source):
You can put this solution on YOUR website!
9x^2+1=6x
First let's but this in standard form;
9x%5E2-6x%2B1=0
discriminant;
b%5E2-4ac
a=9
b=-6
c=1
Now we plug these in;
-6%5E2-4%289%29%281%29
36-36=0
Since the discriminant is 0, there is one real root.
Now use the discriminant in the quadratic equation to find the number;
%28-6%2B-sqrt%280%29%29%2F2%289%29
-6%2F18+=+1%2F3
If the discriminant is negative, there are no real roots;
If the discriminant is positive, there are two real roots.
:)