SOLUTION: write an equation of the line containing the given point and parellel to the given line. express you answer in the form y=mx+b.
(-4,2); 6x=5y+7
1. The first concept you shoul
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-> SOLUTION: write an equation of the line containing the given point and parellel to the given line. express you answer in the form y=mx+b.
(-4,2); 6x=5y+7
1. The first concept you shoul
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Question 161998: write an equation of the line containing the given point and parellel to the given line. express you answer in the form y=mx+b.
(-4,2); 6x=5y+7
1. The first concept you should know is that if two lines are parallel to each other then they have the same slope
2. To be able to write the equation of a line you need either a) two points on the line; or b)a point and a slope
3. Your case is b) a point (-4/2) and a slope (which you should be able to obtain after you simplify 6x=5y+7 into y=mx+b form--m will be the slope)
So:
6x = 5y+7
6x-7=5y
(6x-7)/5=5y/5
(6x-7)/5=y
6x/5-7/5=y
or
(6/5)x-7/5=y (m=6/5 and b=-7/5 for this line)
so the slope for our line must be 6/5 and the point is (-4,2) lets put this into our point-slope formula:
y-y_1=m(x-x_1)
y-2=6/5(x--4)
y-2=6/5(x+4) (a negative time a negative equals a positive)
y-2=6/5x+24/5 used distributive property
y-2+2=6/5x+24/5+2
y=6/5x+24/5+10/5
y=6/5x+34/5 Found 2 solutions by eperette, tnhelsel:Answer by eperette(173) (Show Source):
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