SOLUTION: one number is 5 greater than another number.if the sum of their squares is 5 times the square of the smaller number,what are the numbers?

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Question 161995: one number is 5 greater than another number.if the sum of their squares is 5 times the square of the smaller number,what are the numbers?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let n be the smaller number.
Then the larger number is n%2B5
You are given
n%5E2+%2B+%28n%2B5%29%5E2+=+5n%5E2
n%5E2+%2B+n%5E2+%2B+10n+%2B+25+=+5n%5E2
0+=+3n%5E2+-+10n+-+25+
0+=+%283n+%2B+5%29%28n-5%29
So either 3n%2B5=0 or n-5=0
so n is either -5%2F3 or 5
Check value for n works. 5 does. does -5/3?