SOLUTION: Please help, thank you.
At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi
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At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi
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Question 161991: Please help, thank you.
At 1:00 p.m., a car leaves a city and travels north at a rate of 55 mi/h. An hour later, a second car leaves the city and travels south at a rate of 60 mi/hr. At what time will the two cars be 285 miles apart? Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! Let t = amount of time northbound car traveled
then because the southbout left an hour later
t-1 = amount of time the southbound car traveled
.
Using the distance formula: d = rt
where
d is distance
r is rate or speed
t is time
.
"distance traveled by northbound" + "distance traveled by southbound" = "distance apart"
55t + 60(t-1) = 285
55t + 60t - 60 = 285
115t = 345
t = 3 hours (time traveled by northbound car)
.
Since he started at 1:00 p.m
Adding 3 hours to that will mean that at
4:00 p.m. (the cars are 285 miles apart)
