SOLUTION: What is the standard equation of the circle with radius 4, and center (0,0)? A (x+4)^2 + y^2 = 16 B (x+4)^2 + (y+4)^2 = 16 C (x+4)^2 + (y+4)^2 = 0 D x^2 + y^2 = 0 E ^2 + y^

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: What is the standard equation of the circle with radius 4, and center (0,0)? A (x+4)^2 + y^2 = 16 B (x+4)^2 + (y+4)^2 = 16 C (x+4)^2 + (y+4)^2 = 0 D x^2 + y^2 = 0 E ^2 + y^      Log On


   

Question 161959: What is the standard equation of the circle with radius 4, and center (0,0)?
A (x+4)^2 + y^2 = 16
B (x+4)^2 + (y+4)^2 = 16
C (x+4)^2 + (y+4)^2 = 0
D x^2 + y^2 = 0
E ^2 + y^2 = 4
F x^2 + y^2 = 16

I have no idea where to start on this. Id apperciate seeing the steps and the correct answer. Thank you so much for all your help!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
The formula for any circle is %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 where the center is at (h,k) and the radius is "r"


So in this case, the center is (0,0) which means that h=0 and k=0. Also, the radius is 4 which means that r=4


So the equation goes from %28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 to %28x-0%29%5E2%2B%28y-0%29%5E2=4%5E2 after plugging in the given data

Now simplify to get x%5E2%2By%5E2=16


So the answer is F