SOLUTION: what quanity of a 70% acid solution must be mixed with a 40% solution to produce 450ml of a 60% solution?

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Question 161942: what quanity of a 70% acid solution must be mixed with a 40% solution to produce 450ml of a 60% solution?
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Mixing Acids

This problem can be solved by a system of equations. The first step though is to define your variables correctly. Because our unknowns are volumes, we can call the volume of solution A a and the volume of B b.
We know from the problem that the total volume is 450. Since that total is made up of combining A & B, we can write it as their sum:
a%2Bb=450
The other equation is devised by realizing that the amount of acid contributed by each solution is equal to its volume times its percentage. Thus acid a would contribute a times 70 and b would contribute b * 40. The final volume of acid will also be equal to the (450) times the final percentage of this solution (60). This gives:
70%2Aa%2B40%2Ab=450%2A60
We have now successfully converted from English to math and can solve our two equations. In this example, it's easier done with substitution. Rewriting our first equation solving for a, we get:
a=450-b
Substituting this into to equation 2 for a gives:
70+%2A+%28450-b%29+%2B+40%2Ab+=+450%2A60 Distributing on left & solving right side gives:
31500+-+70%28b%29+%2B+40%2Ab+=+27000 Rearrange combining b's and constants to get:
-30%2Ab=-4500Dividing both sides by -30 gives:
b=150 don't forget the units mL.
This can then be put back into the equation:
a=450-bsubstituting for b gives:
a=450-150 giving the volume a as:
a=300 mL.