SOLUTION: find the measure of an angle such that the difference between its supplement and three times its compliment is 16 degrees.

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Question 161932: find the measure of an angle such that the difference between its supplement and three times its compliment is 16 degrees.
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

A%2BB=90%5Eo, complementary angles
A%2BB=180%5Eo, supplementary angles
Via condition:
%28180-B%29-3%2890-B%29=16%5Eo ----------------> working eqn
180-B-270%2B3B=16%5Eo
2B=16%2B270-180=106%5Eo
cross%282%29B%2Fcross%282%29=cross%28106%2953%2Fcross%282%29
B=53%5Eo ANSWER
.
Complement Angle: A=90-B=90-53=37%5Eo
Supplement Angle: A=180-53=127%5Eo
Check via working eqn:
180-53-3%2890-53%29=16%5Eo
127-3%2837%29=16%5Eo
127%5Eo-111%5Eo=16%5Eo
16%5Eo=16%5Eo
Thank you,
Jojo