Question 161684: Five girls live in the same apartment building. To determine the age of each girl, write each clue as an equation or an equality.
1. All five girls are older than 10 but younger than 20.
2. Karen is older than Angela but younger than Janet.
3. Janet's age is halfway between Tamara's age and Angela's age.
4. the ages of all the girls except Janet are even numbers.
5. Susan is neither the oldest nor the youngest.
6. Karen is as much older than Angela as Tamara is older than Susan.
7. No two girls are the same age.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Five girls live in the same apartment building. To determine the age of each girl, write each clue as an equation or an equality.
:
1. All five girls are older than 10 but younger than 20.
All girls >10, <20
:
2. Karen is older than Angela but younger than Janet.
K > A; K < J
and therefore
J > 14
:
3. Janet's age is halfway between Tamara's age and Angela's age.
J = 
Since J > 14, & J > K & A < K, & J's age is odd,
it has to half-way between 12 and 18
J = 15 yrs
:
4. the ages of all the girls except Janet are even numbers.
Ages. 12, 14, 16, 18 except J
:
5. Susan is neither the oldest nor the youngest.
S = 14 or 16
:
6. Karen is as much older than Angela as Tamara is older than Susan.
K - A = T - S
From this we know T = 18, S = 16
:
7. No two girls are the same age.
:
The following seems to fit all the clues
A = 12
K = 14
J = 15
S = 16
T = 18
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