SOLUTION: At noon Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 mph. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If
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Question 161625: At noon Tom leaves in his boat from a dock and heads south. He travels at a rate of 25 mph. Ten minutes later, Mary leaves the same dock in her speedboat and heads after Tom. If she travels at a rate of 30 miles per hour at what time will she catch up with Tom? Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 25T=30(T-1/6)
25T=30T-5
25T-30T=-5
-5T=-5
T=1 HOUR IS THE CATCH-UP TIME FOR MARY.
PROOF:
25*1=30(1-1/6)
25=30*5/6
25=150/6
25=25 MILES IS THE DISTANCE TRAVELED BEFORE THE CATCH-UP.
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