SOLUTION: On my worksheet it states:
Write an equation of the line that passes through the point at (4,4) and is perpendicular to the line whose equation is 2x+y=7.
I am totally lost and I
Algebra ->
Equations
-> SOLUTION: On my worksheet it states:
Write an equation of the line that passes through the point at (4,4) and is perpendicular to the line whose equation is 2x+y=7.
I am totally lost and I
Log On
Question 161597: On my worksheet it states:
Write an equation of the line that passes through the point at (4,4) and is perpendicular to the line whose equation is 2x+y=7.
I am totally lost and I have to show my work.
Please help.
Thanks Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! First determine the slope of 2x+y=7
Do this by putting it into the "slope-intercept" form of a line:
y = mx + b
where
m is slope
b is the y-intercept at (0,b)
.
2x+y=7
y= -2x+7
From the above, we now see that the slope is -2.
.
For TWO lines to be perpendicular, the slope of the perpendicular line is the "negative reciprocal" of the slope of the original line.
Let m = our new slope
then
m(-2) = -1
m = -1/(-2)
m = 1/2
This slope (1/2) along with the given point (4,4) can be plugged into the "point-slope" form and solved:
.
y - y1 = m(x-x1)
y - 4 = (1/2)(x-4)
2y - 8 = x-4
2y = x+4
y = (1/2)x + 2 (this is what they're looking for)
