SOLUTION: A purse containing only P5 and P10 coins, has 6 more P10 coins than P5 coins. The total value of the money is P360, how many P5 coins and P10 coins are in the purse. P.S. i

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Question 161583: A purse containing only P5 and P10 coins, has 6 more P10 coins than P5 coins. The total value of the money is P360, how many P5 coins and P10 coins are in the purse.
P.S.
i need the formulation also. tnx
Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

Total number of coins P5=x
Total number of coins P10= x%2B6, six more than P5 coins
Remember:
When total number of P5 coins multiplied by P5 + total number of P10 coins multplied by P10 equals P360.Putting into eqn:
P5x%2BP10%28x%2B6%29=P360, WORKING EQN
P5%2BP10x%2BP60=P360, distribute & combine similar terms then add/subtract
P15x=P360-P60=P300
cross%28P15%29x%2Fcross%28P15%29=cross%28P300%2920%2Fcross%28P15%29, divide P15 to isolate x
x=20 -------------------------> number of P5 coins
20%2B6=26 ----------------------> number of P10 coins
Check via WORKING EQN,
P5%2A20%2BP10%2820%2B6%29=P360
P100%2BP260=P360
P360=P360
Thank you,
Jojo