SOLUTION: Find three consecutive integrers whose sum ia 141.

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Question 161494: Find three consecutive integrers whose sum ia 141.
Answer by Alan3354(69443) About Me  (Show Source):
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Find three consecutive integrers whose sum ia 141.
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The numbers will be n, n+1 and n+2
n + n+1 + n+2 = 141
3n + 3 = 141
3n = 138
n = 46
So it's 46, 47, 48