SOLUTION: can i have the correct answers on this problems as soon as possible plz.. tnx 1+2 over x divided by 7 over x a over b divided by a- 5a over b x-5 over x divided by 2-1 ove

Algebra ->  Complex Numbers Imaginary Numbers Solvers and Lesson -> SOLUTION: can i have the correct answers on this problems as soon as possible plz.. tnx 1+2 over x divided by 7 over x a over b divided by a- 5a over b x-5 over x divided by 2-1 ove      Log On


   

Question 161326: can i have the correct answers on this problems as soon as possible plz.. tnx
1+2 over x divided by 7 over x
a over b divided by a- 5a over b
x-5 over x divided by 2-1 over x
x over 2- 2 over x divided by 1- 2 over x
5 over n+1 - 1 over 2 divided by n+3
Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!

I will use NUM to stand for "numerator" and DEN to
stand for "denominator", so for instance, NUM1 stands for 
the first numerator, DEN1 stands for the first denominator,
NUM2 stands for the second numerator, etc.

Suppose your problem is of this type:

%28%28NUM1%2FDEN1%29%2B%28NUM2%2FDEN2%29%29%2F%28%28NUM3%2FDEN3%29%2B%28NUM4%2FDEN4%29%29

Get LCD of all denominators DEN1, DEN2, DEN3, and DEN4.

Form the fraction LCD%2F1 and put it in parentheses
%28LCD%2F1%29

Multiply all four fractions by %28LCD%2F1%29



Now every one of those denominators will cancel 
entirely into the LCD, and the end result will be
much simpler, like this:

%28TERM1+%2B+TERM2%29%2F%28TERM3+%2B+TERM4%29

The smae principle works well regardless of how many fractions
you have on top or bottom.
--------------------------------------

1+2 over x divided by 7 over x

%281%2B2%2Fx%29%2F++%287%2Fx%29++

Write the 1 as 1%2F1 so that
everything will be a fraction, and put parentheses around
every fraction:

%28%281%2F1%29%2B%282%2Fx%29%29%2F++%28%287%2Fx%29%29++

Get LCD of all denominators 1, x, and x.

Then LCD = x 

Form the fraction x%2F1 and put it in parentheses
%28x%2F1%29

Multiply all three fractions by %28x%2F1%29

%28%28x%2F1%29%281%2F1%29%2B%28x%2F1%29%282%2Fx%29%29%2F++%28%28x%2F1%29%287%2Fx%29%29++

Now every one of those denominators will cancel 
entirely into the LCD, and the end result will be
much simpler, like this:



and that is simply:

%28x%2B2%29%2F7

-------------------------

a over b divided by a- 5a over b 

%28a%2Fb%29%2F%28a-%285a%29%2Fb%29

Write the a as a%2F1 so everything will
be a fraction and put parentheses around everything:

%28%28a%2Fb%29%29%2F%28%28a%2F1%29-%28%285a%29%2Fb%29%29

Get LCD of all denominators b, 1, and b.

Form the fraction b%2F1 and put it in parentheses
%28b%2F1%29

Multiply all four fractions by %28b%2F1%29

%28%28b%2F1%29%28a%2Fb%29%29%2F%28%28b%2F1%29%28a%2F1%29-+%28b%2F1%29%285a%2Fb%29+%29

Now every denominator will cancel 
entirely into the LCD, and the end result will be
much simpler, like this:



which is simply

a%2F%28ba-5a%29

Now we can factor out a on the bottom:

a%2F%28a%28b-5%29%29

Now the a's will cancel, leaving a 1 on top:

   1
cross%28a%29%2F%28cross%28a%29%28b-5%29%29

Answer:  1%2F%28b-5%29

If I have time I'll come back and do the others.
But they're all done the same way.

Edwin