SOLUTION: John and Jim are going on a bike ride. On the trip to Mill Park, they ride at an average of 8 mph on a route that is 4 miles less than the route on the return. They travel 7 mph
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-> SOLUTION: John and Jim are going on a bike ride. On the trip to Mill Park, they ride at an average of 8 mph on a route that is 4 miles less than the route on the return. They travel 7 mph
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Question 161239This question is from textbook Algebra 2
: John and Jim are going on a bike ride. On the trip to Mill Park, they ride at an average of 8 mph on a route that is 4 miles less than the route on the return. They travel 7 mph on the return trip. If it takes them one hour longer to return than to go, how much total time do they spend riding their bicycles? This question is from textbook Algebra 2
You can put this solution on YOUR website! they ride at an average of 8 mph on a route that is 4 miles less than the route on the return. They travel 7 mph on the return trip. If it takes them one hour longer to return than to go, how much total time do they spend riding their bicycles?
:
Let t = travel time on outbound trip
then
(t+1) = travel time on the return trip
:
Write a distance equation: Dist = speed * time
:
Out bound dist + 4 mi = return dist
8t + 4 = 7(t+1)
8t + 4 = 7t + 7
8t - 7t = 7 - 4
t = 3 hrs
then the return trip time:
3 + 1 = 4 hrs
:
Total time in the bikes: 4 + 3 = 7 hrs
:
:
Check solution by finding the dist:
out: 3*8 = 24 mi
back: 4*7 = 28 mi
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difference = 4 mi
