SOLUTION: Hilary rode her horse for 8 miles until it was hurt.Then she walked back home to call a vet. She figures the horse wals twice as fast as she does. the whole trip took 4 hours, so h
Algebra ->
Customizable Word Problem Solvers
-> Travel
-> SOLUTION: Hilary rode her horse for 8 miles until it was hurt.Then she walked back home to call a vet. She figures the horse wals twice as fast as she does. the whole trip took 4 hours, so h
Log On
Question 161162This question is from textbook Crossing the River with Dogs
: Hilary rode her horse for 8 miles until it was hurt.Then she walked back home to call a vet. She figures the horse wals twice as fast as she does. the whole trip took 4 hours, so how fast would Hilary have to walk? This question is from textbook Crossing the River with Dogs
You can put this solution on YOUR website! The equation used in this problem is SpeedXTime=Distance
We know that the entire trip takes 4 hours
Let us designate x as the time that it takes the horse to travel 8 miles
4-x= is designated as the time it takes Hilary to walk back
we also know the ratio of rate 2:1
Let us set up the equation
(Distance/Time)=speed of the horse =8/x
(Distance/Time)=speed of Hilary =8/4-x
We need to make both sides of the eqation equal. In order to do this we need to multiply (8/4-x) by 1/2 since the horse is going 2x the speed of Hilary
8/x=(1/2)(8/4-x)
Simplify by dividing 8 by 2 so that you get 8/x=4/4-x
Cross multiply to get 8(4-x)=4x
Use the distributive property
32-8x=4x
Add 8x to both sides and get
32=12x
Divide both sides by 12
x=1.33 hours it took the horse
4-x=2.67 hours it took Hilary
2.99 or 3 miles per hour
To double check let's plug in values
Speed(Time)=8
(3)2.67)=8.0 miles for Hillary
The horse speed is 8/1.33=6.0 mph
the horse is going 6/3 as fast as Hilary the answer is 2.