SOLUTION: can someone please help me with this problem: Give the equation of the vertical asymptote(s) of the rational function. g(x) = x-3/x^2 - 1

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: can someone please help me with this problem: Give the equation of the vertical asymptote(s) of the rational function. g(x) = x-3/x^2 - 1      Log On


   



Question 161147: can someone please help me with this problem:
Give the equation of the vertical asymptote(s) of the rational function.
g(x) = x-3/x^2 - 1

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
Vertical asymptotes correspond to the zeroes of the denominator of a rational function.
.
Since your function was:
+g%28x%29+=+%28x-3%29%2F%28x%5E2+-+1%29+
.
To find the asymptotes, set the denominator to zero and solve:
x^2 - 1 = 0
x^2 = 1
x = {-1, 1}
.
Therefore, your "vertical asymptotes" are at
x=-1 and x=1