SOLUTION: The perimeter of a rectangle is 100 m. The length is 8 m more than twice the width. Find the demensions. What is the length? ______ m What is the width? ______ m

Algebra ->  Surface-area -> SOLUTION: The perimeter of a rectangle is 100 m. The length is 8 m more than twice the width. Find the demensions. What is the length? ______ m What is the width? ______ m       Log On


   

Question 161098: The perimeter of a rectangle is 100 m. The length is 8 m more than twice the width. Find the demensions.
What is the length? ______ m
What is the width? ______ m

Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
Let W be the width. Let L be the length.
L+=+2W+%2B+8
Perimeter+=+2L+%2B+2W+
100+=+2%282W%2B8%29+%2B+2W+
100+=+4W+%2B+16+%2B+2W+
84+=+6W+
14+=+W+
L+=+2%2A14+%2B+8+
L+=+28+%2B+8
L+=+36
Does 36 + 36 + 14 + 14 = 100?