Question 160791This question is from textbook
: If a line passes through (3,-1) and is perpendicular to the graph of y=(-1/3)x-4,what would the slope-intercept form be?
This question is from textbook
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! If a line passes through (3,-1) and is perpendicular to the graph of y=(-1/3)x-4,what would the slope-intercept form be?
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y=(-1/3)x-4 is the slope-intercept form, so the slope is -1/3
To be perpendicular, the slope of the other line is the negative inverse, or +3
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Then use the slope-intercept and the point:
y-y1 = m*(x-x1) (x1,y1) is (3,-1)
y -(-1) = 3*(x-3)
y+1 = 3x-9
y = 3x - 10
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