SOLUTION: a train leaves the station at 6:00pm traveling west at 80 mi/h. on a parallel track, a second train leaves the station 3 hours later traveling west at 100mi/h. at what time will t
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Question 160740This question is from textbook
: a train leaves the station at 6:00pm traveling west at 80 mi/h. on a parallel track, a second train leaves the station 3 hours later traveling west at 100mi/h. at what time will the second train catch up with the first? This question is from textbook
You can put this solution on YOUR website! a train leaves the station at 6:00pm traveling west at 80 mi/h. on a parallel track, a second train leaves the station 3 hours later traveling west at 100mi/h. at what time will the second train catch up with the first?
:
Let t = travel time of the 1st train
then
(t-3) = travel time of the 2nd train
:
When the 2nd train catches the 1st train, they will have traveled the same distance
:
Write a distance equation: Dist = speed * time
:
2nd train dist = 1st train dist
100(t-3) = 80t
:
100t - 300 = 80t
:
100t - 80t = +300
:
20t = 300
t =
t = 15 hrs, travel time of the 1st train
then
6 PM + 15 hrs = 9 AM on the following day
:
:
Check the solution by confirming that both trains traveled ths same distance
80*15 = 1200 mi
100*12 = 1200 mi
