SOLUTION: A chemist needs 120 milliliters of a 60% solution but has only 44% and 92% solutions available how many milliliters of each should be mixed to get the desired solution?

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Question 160734: A chemist needs 120 milliliters of a 60% solution but has only 44% and 92% solutions available how many milliliters of each should be mixed to get the desired solution?
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
Let X be the volume of 44% solution and Y the volume for 92% solution,
The total volume equation is
1.X%2BY=120
The total concentration equation is
2.0.44X%2B0.92Y=0.60%28120%29
Multiply both sides by 100 to get rid of decimals,
2.44X%2B92Y=7200
Use eq. 1 to get X in terms of Y,
1.X%2BY=120
X=120-Y
Now substitute into eq. 2,
2.44X%2B92Y=7200
44%28120-Y%29%2B92Y=7200
5280-44Y%2B92Y=7200
48Y=1920
Y=40
From eq. 1,
X=120-Y
X=120-40
X=80
Use 80 ml of 44% solution and 40 ml of 92% solution.