SOLUTION: At a sale, all CDs are one price and all tapes are another price. Three CDs and two tapes cost $72. One CD and three tapes cost $52. What are the prices of one CD and one tape?
Algebra ->
Equations
-> SOLUTION: At a sale, all CDs are one price and all tapes are another price. Three CDs and two tapes cost $72. One CD and three tapes cost $52. What are the prices of one CD and one tape?
Log On
Question 160692: At a sale, all CDs are one price and all tapes are another price. Three CDs and two tapes cost $72. One CD and three tapes cost $52. What are the prices of one CD and one tape?
So far I've got:
3c + 2t =72
c + 3t =52
Thanks Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! That's a good start.
.
3c + 2t =72
c + 3t =52
.
Now, let's multiply both sides of the bottom equation by -3:
3c + 2t = 72
-3c - 9t =-156
.
Combine both equations:
3c + 2t = 72
-3c - 9t =-156
-------------------
-7t = -84
t = 12 (dividing both sides by -7)
.
Using the above, we can plug it into equation 2:
c + 3t =52
c + 3(12) =52
c + 36 =52
c = 16
.
Solution:
tapes: $12
cd: $16
