Question 160661This question is from textbook Algebra and Trigonometry Structure and Method book 2
: I have been struggling on how to do this problem and I was wondering if someone could help me? Please and Thank You!! I would deeply appreciate it!!
Let f(x)=x^2-1 and g(x)=1-2x. Find the idicated values.
g(1/f(3))
This question is from textbook Algebra and Trigonometry Structure and Method book 2
Answer by gonzo(654)   (Show Source):
You can put this solution on YOUR website! f(x) = x^2 - 1
g(x) = 1 - 2*x
g(1/f(3))
first i think you want to find f(3)
since f(x) = x^2 - 1, then f(3) is found by substituting 3 for x, and you get
3^2 - 1 = 9 - 1 = 8
since f(3) equals 8, then 1/f(3) must equal 1/8.
gj(1/f(3)) is g(x) after you replaced x with (1/f(3)).
since g(x) = 1 - 2*x, then g(1/f(3)) is found by substituting 1/f(3) for x, and you get g(1/f(3)) = 1 - 2 * (1/f(3)).
since you know that 1/f(3)) is 1/8, you substitute 1/8 for 1/f(3)) and the equation becomes 1 - 2 * (1/8) which becomes 1 - 2/8 which becomes 1 - 1/4 which becomes 3/4.
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answer is g(1/f(3)) = 3/4 if i did this right.
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