SOLUTION: Paul and John are riding bicycles on the same path and in the same direction. Paul is going 5 mph and passes a lemonade stand at 12:00 noon. John is going 7 mph and passes the sa

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Paul and John are riding bicycles on the same path and in the same direction. Paul is going 5 mph and passes a lemonade stand at 12:00 noon. John is going 7 mph and passes the sa      Log On

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Question 160637: Paul and John are riding bicycles on the same path and in the same direction. Paul is going 5 mph and passes a lemonade stand at 12:00 noon. John is going 7 mph and passes the same lemonade stand at 12:12. What time does John catch Paul? How far are they from the lemonade stand then?
I'm very confused, I can't seem to find a starting point to put this word problem into an equation. If I could just have help laying out the equation, I think I could solve the problem. Thank you

Answer by checkley77(12844) About Me  (Show Source):
You can put this solution on YOUR website!
5t=7(t-2.2)
5t=7t-15.4
5t-7t=-15.4
-2t=-15.4
t=-14.4/-2
t=7.2 hours John will catch up with Paul.
Paul distance=5*7.2=36 miles from the lemonade stand.
12+7.2=19.2 hours or 7:12 PM they will meet.