SOLUTION: My review has (x-11)(x-8) > 0 I got 8 < x > 11 but the answer was 8 > x > 11 I don't understand why

Algebra ->  Inequalities -> SOLUTION: My review has (x-11)(x-8) > 0 I got 8 < x > 11 but the answer was 8 > x > 11 I don't understand why      Log On


   



Question 160478This question is from textbook
: My review has
(x-11)(x-8) > 0
I got 8 < x > 11
but the answer was 8 > x > 11
I don't understand why
This question is from textbook

Answer by Edwin McCravy(20086) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-11%29%28x-8%29+%3E+0
I got 8+%3C+x+%3E+11
but the answer was 8+%3E+x+%3E+11

That's not correct.  Sometimes answers in books are wrong.
But your answer is wrong too.  "8+%3C+x+%3E+11" is NEVER written.
In an inequality with more than two sides or parts, all the
inequalities must be pointed the same way.  That is a rule
which must be followed.  

The correct answer is

matrix%281%2C3%2Cx%3C8%2C+OR%2C+x%3E11%29

And that is the only way to write it, unless you use
interval notation, which is

 

Graphed on a number line the solution is

<==============================o--------o======>
-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13   

Do you want to know how to solve it correctly?

Here is how:

%28x-11%29%28x-8%29+%3E+0

The left side becomes 0 if x=11 or if x=8.

Draw this number line:

<--------------------------------------------->
-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13  

Draw open circles at 11 and 8

<------------------------------o--------o----->
-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13 

Choose any value left of x=8, say x=0. Plug it in

%28x-11%29%28x-8%29+%3E+0
%280-11%29%280-8%29+%3E+0
%28-11%29%28-8%29+%3E+0
88%3E0

That is true so shade the whole side left of 8

<==============================o--------o----->
-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13

Choose any value right of x=8 that is also left of 11,
say x=9. Plug it in

%28x-11%29%28x-8%29+%3E+0
%289-11%29%289-8%29+%3E+0
%28-2%29%281%29+%3E+0
-2%3E0

That is false so we DO NOT shade the part between
8 and 11. So we still have:

<==============================o--------o----->
-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13

Choose any value right of x=11, say x=12. Plug it in

%28x-11%29%28x-8%29+%3E+0
%2812-11%29%2812-8%29+%3E+0
%281%29%284%29+%3E+0
4%3E0

That is true so shade the whole side right of 8

<==============================o--------o======>
-2 -1  0  1  2  3  4  5  6  7  8  9 10 11 12 13

So to describe where a number x is located on that
number line you say: 

"x is either less than 8 OR x is greater than 11"

matrix%281%2C3%2Cx%3C8%2C+OR%2C+x%3E11%29

or in interval notation:



Edwin