You can put this solution on YOUR website! factor out 3 from 3b^2-24b+48 to get 3(b^2-8b+16)
(b^2-8b+16)can be factored by finding 2 numbers multiplied together gives a product of 16 but when added together gives you -8
It is obvious that the numbers must be both negative (-)(-)=(+)
A likely choice is -4 (-4)(-4)=16 and (-4)+(-4)=-8
Therefore (b^2-8b+16)=(b-4)(b-4)
[36b/3(b-4)(b-4)][3(b-4)/6b] you divided 36b by 6b and get 6(3(b-4)/3(b-4)(b-4)
simplify by canceling out the 3(b-4) terms in the numerator and denominator and you are left with 6/b-4
